Based on VSEPR theory, the number of 90 degree F–Br–F angles in BrF 5 is :
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
0 or 8
Sol. The spatial arrangement of six electron clouds (five bond pairs and one lone pair) round the central Br-atom is octahedral. Due to the presence of one lone pair of electrons in the axial hybrid orbital, the shape of BrF 5 gets distorted and becomes square pyramidal. Basal F-atoms are slightly displaced upwards from the base of the square pyramid.

Br – F(b) distance = 1.79 Å
Br – F(a) distance = 1.68 Å
F(b) – Br – F(b) angle = 89º 48'
F(b) – Br – F(a) angle = 86º 30'
F(b) – Br – e angle = 93º 30'
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems